0=4x^2+100x-336

Solution for 0=4x^2+100x-336 equation:

0=4x^2+100x-336

We move all terms to the left:

0-(4x^2+100x-336)=0

We add all the numbers together, and all the variables

-(4x^2+100x-336)=0

We get rid of parentheses

-4x^2-100x+336=0

a = -4; b = -100; c = +336;
Δ = b2-4ac
Δ = -1002-4·(-4)·336
Δ = 15376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15376}=124$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-124}{2*-4}=\frac{-24}{-8}
=+3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+124}{2*-4}=\frac{224}{-8}
=-28
$